Chemistry, 05.07.2019 18:00, graay0817

How many moles of mgcl2 are there in 308

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answered: alainacorkell5364

Answer is: there are 3.23 moles of magnesium chloride (MgCl₂).

m(MgCl₂) = 308 g; the mass of the magnesium chloride.

M(MgCl₂) = 95.21 g/mol; molar mass of the magnesium chloride.

n(MgCl₂) = m(MgCl₂) ÷ M(MgCl₂).

n(MgCl₂) = 308 g ÷ 95.21 g/mol.

n(MgCl₂) = 3.23 mol; the amount of the magnesium chloride.

answered: aroman4511

The answer is 3.23 mol.

Given data:

Mass in gram of MgCl2 = 308

Molecular mass = 95.21 g/mol

Number of moles = ?

Solution:

Formula:

Number of moles = Mass in grams / Molecular mass

By putting the values in above formula:

Number of moles = 308 / 95.21

= 3.23 mol

So if the weight of MgCl2 is 308 grams. So by the formula of number of moles, it will contain 3.23 moles. Mass in grams of MgCl2 is divided by its molecular mass to get number of moles of MgCl2.

answered: Guest

This is what i found on google “when one phosphate group is removed by breaking a phosphoanhydride bond in a process called hydrolysis, energy is released, and atp is converted to adenosine diphosphate (adp). likewise, energy is also released when a phosphate is removed from adp to form adenosine monophosphate (amp).” i hope this you .

answered: Guest

Answer: abeexplanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.