What is the axmen classification for chbrclf?

Answer is: Molecule is tetrahedral.

CHBrClF (bromochlorofluoromethane) is a chemical compound with one of the simplest possible stable chiral compounds.

VSEPR theory (The Valence Shell Electron Pair Repulsion Theory) uses the AXE notation (m and n are integers, m + n = number of regions of electron density).

For bromochlorofluoromethane:

m = 4; the number of atoms bonded to the central atom.

n = 0;  the number of lone pairs on the central atom.

According to VSEPR theory, the "AXE method" is used for counting electrons around the central atom, where A is the central atom, X is the ligand that make a covalent bond with the central atom and E is the number of lone pair of electrons on the central atom.

In CHBrClF, The central carbon atom is bound to four ligands and has no lone pair of electrons. Therefore, the classification for CHBrClF is AX₄E₀. And as expected from the axmen classification, CHBrClF (AX₄E₀) has a tetrahedral molecular geometry and tetrahedral electron domain geometry.

the answers would be

the first one and the second one