Amixture of f2, h2 and xe have mole fractions of 0.25, 0.65, and 0.10, respectively. what is the pressure of f2 if the total pressure of the mixture is 3.9 atm?

Answer : The pressure of is 0.975 atm.

Solution : Given,

Mole fraction of = 0.25

Mole fraction of = 0.65

Mole fraction of = 0.10

Total pressure of mixture = 3.9 atm

According to the Dalton's law of partial pressure, which tells that the partial pressure of a gas is directly proportional to the mole fraction of a gas.

where,

= partial pressure of a gas

= mole fraction of a gas

= total pressure of gas

Now we have to calculate the partial pressure of gas.

Put all the given values in above formula, we get

The partial pressure of is 0.975 atm.

given the reactants, h2so4 and koh, we are asked to determine the product(s) of the reaction. since h2so4 is an acid and koh is a base. this is a neutralization reaction, thus, the products are salt and water. 

so, h+ from h2so4 will react with oh- from koh forming h2o. k+ will also react with so4 2- forming k2so4. therefore, the balanced reaction will be:

h2so4 + 2koh > k2so4 + 2h2o

explanation:

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