Consider the equilibrium: hcooh(aq) + f-(aq) < > hcoo-(aq) + hf (aq) given that the ka of hcooh = 1.8 x 10-4 and the ka of hf = 6.8 x 10-4, calculate the equilibrium constant and predict whether the equilibrium favors reactants or products. 0.265; reactants 3.8 x 10-8; reactants 3.0 x 10-9; reactants 3.8; products

Hey there!:

K = Ka * Kb / Kw

Ka = 1.8*10⁻⁴

Kb = 10⁻¹⁴ / 6.8*10⁻⁴

K =  1.8*10⁻⁴ * ( 10⁻¹⁴/ 6.8*10⁻⁴ ) * ( 1 / 10⁻¹⁴ )

K =  = 1.8 / 6.8

K = 0.265

Answer A

Therefore:

K is less than on the forward reaction is not favorable .

Hope That helps!

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.