Chemistry, 06.07.2019 19:00, maddy6882

At 2000 ∘c the equilibrium constant for the reaction 2no(g)⇌n2(g)+o2(g) is kc=2.4×103. you may want to reference (pages 641 - 644) section 15.6 while completing this problem. part a if the initial concentration of no is 0.175 m, what is the equilibrium concentration of no? g

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answered: kmc3490

The equilibrium concentration of NO is $\boxed{{\text{0}}{\text{.0018 M}}}$ .

Further Explanation:

Chemical equilibrium is a stage where the rate at which forward reaction proceeds becomes equal to the rate at which the backward reaction occurs. At equilibrium, the formation of product from reactant gets balanced out by the formation of reactants from products so there is no change in concentrations of both reactants and products.

The expression for a general equilibrium is,

$a{\text{A}} + b{\text{B}} \rightleftharpoons c{\text{C}} + d{\text{D}}$

Here,

A and B are the reactants.

C and D are the products.

a and b are the stoichiometric coefficients of reactants.

c and d are the stoichiometric coefficients of products.

The expression for the equilibrium constant for the general reaction is as follows:

${K_{\text{c}}}=\dfrac{{{{\left[ {\text{C}} \right]}^c}{{\left[ {\text{D}} \right]}^d}}}{{{{\left[ {\text{A}} \right]}^a}{{\left[ {\text{B}} \right]}^b}}}$

Here,

${K_{\text{c}}}$ is the equilibrium constant.

[C] is the concentration of C.

[D] is the concentration of D.

[A] is the concentration of A.

[B] is the concentration of B.

The given reaction occurs as follows:

$2{\text{NO}}\left( g \right) \rightleftharpoons {{\text{N}}_2}\left( g \right) + {{\text{O}}_{\text{2}}}\left( g \right)$

The initial concentration of NO is 0.175 M. Let x to be the change in concentration at equilibrium. Therefore, the concentration of NO becomes 0.175-2x at equilibrium. The concentration of both ${{\text{N}}_{\text{2}}}$ and ${{\text{O}}_{\text{2}}}$ become x at equilibrium.

The expression of ${K_{\text{c}}}$ for the above reaction is as follows:

${K_{\text{c}}}=\dfrac{{\left[ {{{\text{N}}_2}} \right]\left[{{{\text{O}}_2}} \right]}}{{{{\left[ {{\text{NO}}} \right]}^2}}}$ …… (1)

Substitute x for ${{\text{N}}_{\text{2}}}$ , x for ${{\text{O}}_{\text{2}}}$ , 0.175-2x for [NO] and $2.4 \times {10^3}$ for ${K_{\text{c}}}$ in equation (1).

$2.4 \times {10^3} = \dfrac{{\left( {\text{x}}\right)\left({\text{x}} \right)}}{{{{\left( {0.175 - 2x}\right)}^2}}}$ …… (2)

Solve for x,

${\text{x}} = 0.0866$

Or,

${\text{x}} = 0.0884$

The value of ${\text{x}} = 0.0884$ is rejected as it makes concentration of NO negative that is not possible. So the value of x is 0.0866.

The concentration of NO at equilibrium is calculated as follows:

$\begin{aligned}\left[ {{\text{NO}}} \right]&= 0.175 - 2\left( {0.0866} \right)\\&= {\text{ 0}}{\text{.0018 M}}\\\end{aligned}$

Learn more:

Calculate equilibrium constant for ammonia synthesis: Complete equation for the dissociation of (aq):

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Equilibrium

Keywords: chemical equilibrium, reactants, products, concentration, A, B, C, D, a, b, c, d, kc, equilibrium constant, 0.0018 M, NO, N2, O2.

answered: Guest

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

answered: Guest

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

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At 2000 ∘c the equilibrium constant for the reaction 2no(g)⇌n2(g)+o2(g) is kc=2.4×103. you may want...