At 189k a sample of gas has a volume of 32.0cm. what does the gas occupy at 242k

At 189 K volume = 32.0 cm

As volume of gas is directly proportional to temperature.

As the temperature increase the volume of gas will also increase.

so

Volume at 1 K =  32/189

Volume at 242 K = 32/189 * 242 = 40.97 cm.

Gas occupy 40.97 cm volume at 242 K.

the answer is true. hope it .

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2