Contains 63.65% nitrogen and 36.35% oxygen by mass what is the empirical formula for this compound

The empirical formula is NO₂.  

Assume that you have 100 g of the compound.

Then you have 63.65g N and 36.35 g O.

Now, we must convert these masses to moles and find their ratios.

From here on, I like to summarize the calculations in a table.

Element  Mass/g    Moles    Ratio     Integers  

     N         63.65     4.543      1                  1

     O        36.35      2.2719    2.000         2

The empirical formula is NO₂.

-be a crystalline solid

- be soluble in water

-conduct electricity

hope this : )

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j