Afertilizer is 60.9% ammonium phosphate. what is the percent p in the sample? answer in units of % i originally got 20.7685% but it says my answer is wrong. ?

- 12.7%

Solution:- It says, ammonium phosphate is 60.9%. It means if we assume 100 g of the sample then there is 60.9 g ammonium phosphate in it.

Formula of ammonium phosphate is and it's molecular weight is 149 grams per mol. There is only one P in the formula and so the mass of P in 149 g of ammonium phosphate is 31 g(atomic mass of P).

Now, we could use the proportions to find out the mass percentage of P in the sample.

31 g P is present in 149 g of ammonium phosphate, how many grams of P would be present in 60.9 g of ammonium phosphate. Let's set the proportions as:

This 12.7 g of phosphorous is present in 100 g of the sample means there is 12.7% phosphorous in the sample.

they are made of gases.

they have a spherical shape.

they make energy through fusion.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :