It is desired to produce 2.25 grams of dichloromethane (ch2cl2) by the following reaction. if the percent yield of dichloromethane (ch2cl2) is 65.5 %, how many grams of carbon tetrachloride would need to be reacted?carbon tetrachloride methane (ch4)(g) + carbon tetrachloride(g) dichloromethane (ch2cl2)(g)

- 3.12 g carbon tetrachloride are needed.

Solution:- The balanced equation is:

From given actual yield and percent yield we will calculate the theoretical yield that would be further used to calculate the grams of carbon tetrachloride.

percent yield formula is:

percent yield =

theoretical = 3.44 g

From balanced equation, there is 2:1 mol ratio between dichloethane and carbon tetrachloride.

Molar mass of dichloroethane is 84.93 gram per mol and molar mass of carbon tetrachloride is 153.82 gram per mol.

=

So, 3.12 grams of carbon tetrachloride are needed to be reacted.