Convert 77.0 l at 0.24 atm to its new volume at standard pressure.

Knowing the two variables in this problem are volume (liter) and pressure (atm), we can determine that the law ought to be used would be Boyle's Law.

Boyle's Law: P₁v₁=P₂V₂

Using the question, we can find:

P₁ (initial pressure)=0.24 atm

V₁ (initial volume)=77.0L

P₂ (standard pressure)= 1.00atm

V₂=?

We can rearrange the equation to solve for V₂: V₂=P₁V₁/P₂

Next, we can plug in the values: V₂=

We would receive an answer of 18.48 L. However, it appears that the significant digits would be 3 as both 77.0 and 0.24 have 3 digits. As such, the answer would be 18.5L of gas at 1.00atm.

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explanation:

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