Complete combustion of 5.70 g of a hydrocarbon produced 17.3 g of co2 and 8.83 g of h2o. what is the empirical formula for the hydrocarbon?

the equation for the combustion reaction is as follows

CₐHₓ + O₂ ---> CO₂ + H₂O

the coefficients for the compounds are unknown as we dont know the formula of the hydrocarbon yet

the number of moles of CO₂ formed is - 17.3 g / 44 g/mol = 0.39 mol

number of moles of H₂O formed - 8.83 g / 18 g/mol = 0.49 mol

next we have to find the number of moles of C and H present to find the empirical formula of the hydrocarbon

1 mol of CO₂ contains - 1 mol of C

therefore 0.39 mol of CO₂ contains - 0.39 mol of C

1 mol of H₂O contains - 2 mol of H

therefore 0.49 mol of H₂O contains - 2 x 0.49 = 0.98 mol of H

                                           C                          H

number of moles -      0.39 mol                  0.98 mol

divide both by the lesser number of moles

                                    0.39  / 0.39 = 1       0.98 / 0.39  = 2.5

since 2.5 cannot be rounded off we multiply both by 2 to get a number that can be rounded off to a whole number

C - 1 x 2 = 2

H - 2.5 x 2 = 5

therefore empirical formula is C₂H₅

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.