At a constant pressure and a temperature of 280 k the gas in a cylinder has a volume of 10.0 l. if the volume of the gas is increased to 20.0 l what is the new temperature 28 k 560 k 140 k 2800 k

At constant pressure a known moles of gas has volume which is directly proportional to temperature (Charle's Law)

Thus V α T

Therefore

V1/V2 = T1 /T2

V1 = initial volume = 10 L

T1 = initial temperature= 280 K

V2 = final volume = 20L

T2 = final temperature = ?

T2 = T1V2 / V1 = 280 X 20 / 10 = 560 K

Thus the new temperature will also doubles up as volume is increased by two times

answer; economic order quantity;

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g