Answer : The Activation energy, Ea = 201.820 KJ/mol
The Pre-exponential constant, = 1.7658 ×
Solution : Given,
Diffusivity of Ni at , = 1.23 ×
Diffusivity of Ni at , = 1.45 ×
Temperature, = = 1200 + 273 = 1473 K
Temperature, = = 1800 + 273 = 2073 K
Value of R = 8.314 J/mol/K
Formula used :
..........(1)
This formula convert into logarithm term for the calculation of activation energy. So the formula is,
........(2)
Now put all the values in above formula (2), we get
Rearranging the terms, we get the value of Activation energy, (Ea) as
Ea = 201.820 KJ/mol
Now, we have to calculate the value of Pre-exponential constant, bye using formula (1)
now put all the values in formula,we get
Rearranging the terms, we get the value of Pre-exponential constant, as
= 1.7658 ×