Ba(oh)2 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.750 m ba(oh)2 solution.

The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is

[Ba2+] = 0.750 M

[OH-]= 1.50 M

write the equation for dissociation

that is  Ba(OH)2  (s)→ Ba2+(aq)  + 2OH-(aq)

by use of mole ratio of Ba(OH)2 : Ba2+ which is 1: 1 the concentration of Ba2+ is therefore= 0.750M

by use of mole ratio of Ba(OH)2 : OH- which is 1:2 the concentration of  OH- =0.750 M x2/1=1.50 M

sorry idk the answer well to you i have a explaination

explanation: a formula which shows the arrangement of atoms in the molecule of a compound

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