2naoh(aq) + zn(no3)2(aq) → zn(oh)2(s) + 2nano3(aq)the molecular equation you determined in part b is shown above for your convenience. examine each of the chemical species involved to determine the ions that would be present in solution. be sure to consider both the coefficients and subscripts of the molecular equation, and then write this precipitation reaction in the form of a balanced complete ionic equation. express your answer as a chemical equation including phases. type an underscore or a carat (^) to add subscripts and superscripts more quickly.

The molecular equation is

2NaOH(aq) + Zn(NO_3)_2(aq) → Zn(OH)^2(s) + 2NaNO_3(aq)

The net ionic equation will not include the spectator ions it will only includes the other ions

So first let us consider the balanced ionic reaction

2Na^+  + 2OH^-(aq) + Zn^+2 + 2NO3^-1 (aq) → Zn(OH)_2(s) + 2Na^+ + 2NO3-(aq)

spectator ions are

Na+   and NO3^-

So net ionic equation will be

2OH^- (aq) + Zn^+2  → Zn(OH)_2(s)

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph