How many atoms of oxygen are in 1.0 g of k2o2 (mw 110.0)?

Given

Mass of K2O2 = 1.0 g

Molar mass of K2O2 = 110.0 g/mol

Calculate the # moles of K2O2

# moles = mass of K2O2/molar mass

            = 1.0 g/110.0 g.mol-1 = 0.0091 moles

1 mole of K2O2 contains 2*6.023*10^23 atoms of oxygen

Therefore, 0.0091 moles of K2O2 will correspond to:

= 0.0091 moles * 2* 6.023*10^23 atoms/1 mole

= 1.096 * 10^24 atoms of oxygen

h let me think