Ametal object has a mass of 8.37g. when it was in a graduated cylinder containing 20.0 ml of water, the water level rose to 23.1 ml. what is the density and identity of the metal

The density and identity of the metal would be 2.7 g/ml and aluminum respectively

Mathematically, density = mass/volume

Mass of the object = 8.37 g

Volume of the object = 23.1 - 20

                                 = 3.1 ml

Density of object = 8.37/3.1

                               = 2.7 g/ml

Thus, the density of the object is 2.7 g/ml and the object is most likely an aluminum metal.

More on density can be found here: link

Mass of metal is 8.37 g, volume of water in graduated cylinder is 20 mL. After adding the metal, water level increases to 23.1 mL. The volume of metal is equal to the increase in water level.

The increase in water level can be calculated by taking difference of final and initial level of water.

Thus,

Density of metal is defined as mass per unit volume of metal. It can be calculated as follows:

This value corresponds to the density of aluminum.

Therefore, density is 2.7 g/mL and metal is aluminum.

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.