How many kilograms of chlorine are in 21 kg of cf2cl2

Answer : The mass of chlorine present in sample is 12.32 kilograms.

Explanation :  Given,

Mass of = 21 kg = 21000 g     (1 kg = 1000 g)

First we have to calculate the moles of .

Molar mass of = 121 g/mole

Now we have to calculate the moles of chlorine.

In the molecule , there are 1 mole of carbon, 2 moles of fluorine and 2 moles of chlorine.

As, 1 mole of contains 2 moles of chlorine

So, 173.5 moles of contains moles of chlorine

Now we have to calculate the mass of chlorine.

Molar mass of chlorine = 35.5 g/mole

Therefore, the mass of chlorine present in sample is 12.32 kilograms.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j