Isopropanol (c3h8o) is a key ingredient in some hand sanitizers. suppose that 127 grams of isopropanol is dissolved in water. the volume of the solution is 1,250 milliliters. what is the molarity of the solution? refer to the periodic table to you answer. express your answer to three significant figures. the molarity of the solution is m.

- 1.69M

Solution:- Molarity is moles of solute per liter of solution. We have 127 grams of the solute, isopropanol and the volume of the solution is 1250 mL. We need to convert the grams to moles and the mL to L.

Molar mass of  = 3(12.011) + 8(1.008) + 1(15.999)  = 60.096 gram per mol

Let's convert the grams to moles as:

= 2.11 mol

The volume is 1250 mL that is 1.25 L.

= 1.69M

So, the molarity of the solution is 1.69M.

1.69 M

Explanation:

1) Data:

a) mass of solute: 127 g

b) volume of solute: 1,250 ml = 1.25 liters

c) compound: C₃H₈O

d) M = ?

2) Formulae:

a) M = number of moles of solute / volume of solution in liters

b) number of moles = mass in grams / molar mass

3) Solution

a) molar mass of C₃H₈O:

element      number of atoms      atomic mass      mass of the element

                                                      a.m.u.                  g / mol

C                  3                                 12.011                   3 × 12.011 = 36.033

H                  8                                  1.008                  8 × 1.008 = 8.064

O                  1                                  15.999                 15.999

                                             Sum = molar mass =     60.096 g/mol

b) number of moles = mass in grams / molar mass = 127 g / 60.096 g/mol = 2.113 mol

c) M = number of moles of solute / volume of solution in liters = 2.113 mol / 1.250 liter = 1.69 M (showing 3 significant figures).

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products