If 1.87 g‎ of acetic acid (ch3co2h)‎ reacts with 2.31 g‎ of isopentylalcohol (c5h12o)‎ to give‎ 3.20 g of isopentylacetate (c7h14o2)‎, what is the percent yield of the reaction?

The reaction of acetic acid with isopentyl alcohol is

CH3COOH + C5H12O  ---> C7H14O2  + H2O

Thus one mole of acetic acid reacts with one mole of isopentyl alcohol to give one mole isopentyl acetate

Molar mass of acetic acid = 60.05 g / mole

Moles of acetic acid used = Mass used  / Molar mass = 1.87/ 60.05 = 0.0311

Molar mass of isopentyl alcohol = 88.15 g / mole

Moles of isopentyl alcohol = Mass / Molar mass = 2.31 / 88.15 = 0.0262

Molar mass of isopentyl acetate = 130.19 g / mole

Moles of isopentyl acetate = 3.20 / 130.19 = 0.0246

As per equation 0.0262  should of isopentyl alcohol should react with 0.0262 moles of acetic acid to give 0.0262 isopentyl acetate

Thus theoretical yield = 0.0262 moles

Actual yield = 0.0246

% yield = Actual yield X 100 / theoretical yield = 0.0246 X 100 / 0.0262 = 93.89%

c8h10 is your answerr

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.