How much energy must be supplied to break a single aluminum-27 nucleus into separated protons and neutrons if an aluminum-27 atom has a mass of 26.9815386 amu? (the mass of an electron is 5.485799×10−4 amu, the mass of a proton is 1.0072765 amu, and the mass of a neutron is 1.0086649 amu.) express your answer using six significant figures. g?

Solution: For calculating nuclear binding energy we need to find the binding energy and that can be calculated by mass defect. Mass defect is the excess mass present in any isotope.

nucleus having 13 protons as it is visible from atomic number and number of neutrons is 14 which is calculated from .

As it is given in the question that and , we can calculate the mass of the isotope.

Mass defect or = mass of isotope - atomic mass.

As the mass is expressed in kilograms do to convert it into kilograms, we need to use the conversion

To calculate energy binding energy we will use the formula

where c= speed of light

Nuclear binding energy is expressed in kJ/mol of nuclei, so for that we need to convert Joules to kJ by conversion and converting individual particles into moles, we need to multiply it by avagadro's number that is .

Amount of energy to break down the energy of a single bond of   nuclei is

the answer is 0.8m.

by: nicholas