Apiece of gold wire has a diameter of 0.175 cm. how much will precisely 1.00 x 10^5 of the wire weight?

Given data:

Diameter of the gold wire (d) = 0.175 cm

Length of the gold wire (l) = 1.00 * cm

Volume of the given gold wire = volume occupied by a cylindrical object\

                                       = π * *l

here r = radius of the cross section

where : r = d/2

Hence the volume V = π * *l

            =

Density of gold = 19.3 g/cm3

Weight of the gold wire = Density * volume

= *

=

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be