A3.00- g sample of an alloy (containing only pb and sn) was dissolved in nitric acid (hno3). sulfuric acid was added to this solution, which precipitated 1.69 g of pbso4. assuming that all of the lead was precipitated, what is the percentage of sn in the sample?

The reaction between Pb and H2SO4 will be

Pb+2  + SO4^-2 = PbSO4(s)

So each mole of Pb will give one mole of PbSO4

Moles of PbSO4 obtained = mass / molar mass = 1.69 / 303.26 = 0.0056 moles

Moles of Pb present = 0.0056

Mass of Pb present = moles X atomic mass = 0.0056 X 207 = 1.16 grams

So mass of Sn in sample = 3 - 1.16 = 1.84

% of Sn = Mass of Sn X 100 / total mass = 1.84 X 100 / 3 = 61. 33%

b is the correct answer

mark me brainliest and hope this

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.