If 28 ml of 5.4 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?

A reaction between acid and base to form water and salt is known as neutralization reaction. It is a double replacement reaction.  

The reaction between and will be:

The balanced reaction is:

Volume of = 28 mL (given)

Since, 1 L = 1000 mL

So, 28 mL = 0.028 L

Molarity of = 5.4 M (given)

Molarity =   -(1)

Substituting the values in equation (1):

From the balanced reaction between and , 2 moles of reacts with 1 mole of .

Molar mass of = 84.007 g/mol

Mass of needed:

=

Hence, the required amount of is .

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explanation: