You have 15.5 g of oxalic acid, h2c2o4.what amount is represented by 15.5 g of oxalic acid? how many molecules of oxalic acid are in 15.5 g? how many atoms of carbon are in 15.5 g of oxalic acid?

a) m(H₂C₂O₄) = 15.5 g.

n(H₂C₂O₄) = m(H₂C₂O₄) ÷ M(H₂C₂O₄).

n(H₂C₂O₄) = 15.5 g ÷ 90 g/mol.

n(H₂C₂O₄) = 0.172 mol; amount of substance.

N(H₂C₂O₄) = n(H₂C₂O₄) · Na (Avogadro constant).

N(H₂C₂O₄) = 0.172 mol · 6.022·10²³ 1/mol.

N(H₂C₂O₄) = 1.037·10²³; number of molecules.

b) In one molecule of oxalic acid there are two atoms of carbon:

N(C) = 2 · N(H₂C₂O₄).

N(C) = 2 · 1.037·10²³.

N(C) = 2.074·10²³; number of carbon atoms.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)