How many pints of a 30% sugar solution must be added to a 5 pint of a 5% sugar solution to obtain a 20% sugar solution?

To obtain the sugar solution of 20%, 7.5 pints of 30% sugar solution have been added.

Since 30% sugar solution has been added to the 5% solution to obtain the total solution of 20%. The volume of 5% solution has been 5 pints, let the amount of 30% sugar solution will be x. The final volume of the 20% sugar solution will be 5 + x.

The dilution formula will be:

The volume of 30% solution concentration + the volume of 5% solution concentration = Volume of 20% solution concentration

x 30 + 5 5 = 20 (5 + x)

30x + 25 = 100 + 20x

10x = 75

x = 7.5 pints.

To obtain the sugar solution of 20%, 7.5 pints of 30% sugar solution have been added.

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You must add 7.5 pt of the 30 % sugar to the 5 % sugar to get a 20 % solution.

You can use a modified dilution formula to calculate the volume of 30 % sugar.

V_1×C_1 + V_2×C_2 = V_3×C_3

Let the volume of 30 % sugar = x pt. Then the volume of the final 20 % sugar = (5 + x ) pt

(x pt×30 % sugar) + (5 pt×5 % sugar) = (x + 5) pt × 20 % sugar

30x + 25 = 20x + 100

10x = 75

x = 75/10 = 7.5

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explanation:

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