If you were presented with 2 l of a 2 m sucrose stock solution, how many grams of sugar would be in a 100 ml aliquot?

Answer;

68.46 g of sucrose in 100mL

Solution and explanation;

Given 2L of 2 mol/L sucrose solution

Moles = concentration x volume

Therefore; The number of moles in this solution is 2 L x 2 mol/L = 4 mol

The molecular mass of sucrose is 342.3 g/mol.

Mass = Moles × Molecular weight

Therefore the mass of sucrose in 2 L;

  = 4 mol x 342.3 g/mol = 1369.2g

but; 2L/20 = 100 mL

= 1369.2/20 = 68.46

Hence; you would have 68.46 g in 100 mL