__ ch3ch2cooh(l) + __ o2(g)  __ co2(g) + __ h2o(l) how many moles of o2 are required to oxidize 1 mole of ch3ch2cooh according to the reaction represented above?

The given chemical equation represents the combustion reaction of propanoic acid:

On balancing we get,

The above balanced chemical equation tells us that, 2 mol require 7 mol for complete combustion to produce and

Given moles of = 1 mol

Calculating moles of required for combustion:

Therefore, 3.5 mol Oxygen is required for complete combustion of 1 mol propanoic acid.

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1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.