Avial of amoxicillin contains 580. mg in 1.8 ml of solution. what volume of the solution contains 190 mg of the drug?

-  0.59 mL

Solution:- From given information, 580 mg of the drug are present in 1.8 mL of solution. It asks to calculate the mL of solution that would contain 190 mg of the dug.

This could easily be solved using ratios as:

On rearranging:

divide both sides by 580mg.

So, 0.59 mL of the solution contains 190 mg of the drug.

your answer would be a. 12.5 kg

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"