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Chemistry, 12.07.2019 01:30, nefertiri64
In a reaction where a + b ab, what does an equilibrium position of a= 14%, b = 14%, and ab= 72% indicate about the reaction? a. because a and b are equal, the reaction has reached equilibrium. b. there is more a and b than ab at equilibrium, and the reaction favors the reactants. c. there is more ab than a and b at equilibrium, and the reaction favors the products. d. there is more ab than a and b at equilibrium, and the reaction favors the reactants. e. the reaction is not at equilibrium.
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In a reaction where a + b ab, what does an equilibrium position of a= 14%, b = 14%, and ab= 72% indi...
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