How many atoms of iron (fe) are in a sample of 7.38 mol fe? 1.23 x 1023 atoms fe 5.58 x 1023 atoms fe 3.37 x 1024 atoms fe 4.44 x 1024 atoms fe

atoms of Fe

Explanation: According to Avogadro's law, 1 mole of every substance contains Avogadro's number of particles. 1 mole of iron atom contains atoms of Fe.

If 1 mole of Fe contains= atoms of Fe.

then 7.38 moles of Fe contains= atoms of Fe.

The amount of iron (Fe) atoms in a sample of 7.38 moles of iron (Fe) is × atoms.

Given the following data:

To find the amount of iron (Fe) atoms in a sample of 7.38 moles of iron (Fe), we would apply Avogadro's law:

Avogadro's law states that at the same temperature and pressure (STP), equal volumes of all gases have the same number of molecules.

Avogadro's constant = ×

1 mole of iron (Fe) = × atoms.

7.38 moles of iron (Fe) = X atoms.

Cross-multiplying, we have:

× ×

X = × atoms

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c. 75.7

i think that is the right

the answers would be

the first one and the second one