Chemistry, 12.07.2019 08:30, Terrydactly

How many atoms of mercury are present in 3.4 cubic centimeters of liquid mercury? the density of mercury is 13.55 g/cc?

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answered: awdadaddda

1.37 × 10²³ Atoms of Mercury

Solution:

Step 1: Calculate Mass of Mercury using following formula,

Density = Mass ÷ Volume

Solving for Mass,

Mass = Density × Volume

Putting values,

Mass = 13.55 g.cm⁻³ × 3.4 cm³ ∴ 1 cm³ = 1 cc

Mass = 46.07 g

Step 2: Calculating number of Moles using following formula;

Moles = Mass ÷ M.mass

Putting values,

Moles = 46.07 g ÷ 200.59 g.mol⁻¹

Moles = 0.229 mol

Step 3: Calculating Number of Atoms using following formula;

Number of atoms = Moles × 6.022 ×10²³

Putting value of moles,

Number of Atoms = 0.229 mol × 6.022 × 10²³

Number of Atoms = 1.37 × 10²³ Atoms of Hg

answered: Guest

a mercury barometer is a device that uses the physical properties of mercury in a tube to measure barometric pressure. mercury barometers are used for : -

1. measurement of atmospheric pressure

2. determining the altitude of a place

3. weather forecasting

4. calibration and checking of aneroid barometers

5. application in fluid mechanics

6. measurement of pressure in aircrafts

7. surface weather analysis

8. preparation of barographs

9. usage in physical sciences like physics, astronomy & chemistry

10. preparation of aircraft altimeters

characteristics of mercury barometer : -

1.used to define and measure atmospheric pressure.

2.on the average at sea level the column of mercury rises to a height of about 760 mm.

3.this quantity is equal to 1 atmosphere.

4.it is also known as standard atmospheric pressure.

5.a barometer in which the weight of a column of mercury in a glass tube with a sealed top is balanced against that of the atmosphere pressing on an exposed cistern of mercury at the base of the mercury column, the height of the column varying with atmospheric pressure.

Write 15 uses of a mercury barometer along with its characterestics

answered: Guest

Hello! data: p (pressure) = 1.25 atmv (volume) = ? (in l)t (temperature) = 298 kn (number of mols) = 0.900 molesr (gas constant) = 0.082 (atm*l/mol*k)apply the data to the clapeyron equation (ideal gas equation), see: $p*v = n*r*t$ $1.25*v = 0.900*0.082*298$ $1.25v = 21.9924$ $v = \dfrac{21.9924}{1.25}$ $v = 17.59392\: \to\: \boxed{\boxed{v\approx 17.6\: l}}\end{array}}\qquad\checkmark$ i hope this . =)

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How many atoms of mercury are present in 3.4 cubic centimeters of liquid mercury? the density of me...