How many grams of pure naoh must be used to prepare 10.0 l of a solution that has a ph of 13? ?

We must use 39.997 grams of NaOH to prepare 10.0 L of a solution that has a pH of 13.

To find the mass of NaOH, we need to calculate the number of moles.  

From the pH, we have:

The pOH is given by

Now, we can find the number of moles with the volume of solution

Finally, we can calculate the mass

Therefore, we need to use 39.997 g of NaOH.

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40 g NaOH. You must use 40 g NaOH to prepare 10.0 L of a solution that has a pH of 13.

Step 1. Calculate the pOH of the solution

pOH = 14.00 – pH = 14.00 -13 = 1

Step 2. Calculate the concentration of NaOH

[NaOH] = [OH^(-)] = 10^(-pOH) mol/L = 10^(-1) mol/L = 0.1 mol/L

Step 3. Calculate the moles of NaOH

Moles of NaOH = 10.0 L solution × (0.1 mol NaOH/1 L solution) = 1 mol NaOH

Step 4. Calculate the mass of NaOH

Mass of NaOH = 1 mol NaOH × (40.00 g NaOH/1 mol NaOH) = 40 g NaOH

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