How many grams of glucose would be present in one liter of a 1 m solution of glucose?

             Mass  =  180 g

Solution:

Step 1: Calculate Moles using following Formula,

                                   Molarity  =  Moles ÷ Volume

Solving for Moles,

                                  Mole  =  Molarity × Volume

Putting values,

                                  Mole  =  1 mol.L⁻¹ × 1 L

                                  Mole  =  1 moles

Step 2: Calculate mass using following formula,

                                  Moles  =  Mass ÷ M.Mass

Solving for Mass,

                                  Mass  =  Moles × M.Mass

Putting Values,

                                  Mass  =  1 mol × 180 g.mol⁻¹

                                  Mass  =  180 g

14 days is the half-life of phosphorus-32

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.