When 8.0 mol mg react with 13.5 mol hci, what is the limiting reactant and how many moles of h2 can be formed?

The answer is :

HCl is the limiting reactant and 6.75 mol can be formed.

The explanation:

1- we need to get the balanced reaction equation:

Mg + 2HCl > MgCl2 + H2

Here, you can see from the balanced chemical equation, that 1 mol Mg reacts with 2 mol HCl.

2-by using stoichiometry for each reactant:

So, 8 mol Mg should react with 2* 8 mol HCl

So, 8 mol Mg should react with 16 mol HCl

But the given amount of HCl is 13.5 mol, which is less than the required (16 mol) to react completely with Mg.

-now Amount of HCl is less So, HCl is the LIMITING REAGENT.

-when limiting reagent (or limiting reactant, LR) in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent.

Also, you can see that 2 mol HCl corresponds to the formation of 1 mol H2.

SO, 1 mol HCl corresponds to the formation of 1/2 mol H2.

1 mol HCl → 1/2 mol H2

13.5 mol HCl→

13.5 mol HCl corresponds to the formation of (1/2)*13.5 mol H2 = 6.75 mol H2.

So, HCl is the limiting reactant, and 6.75 mol H2 can be formed.

idk i’m struggling too

here are some of the ways in which chemical and nuclear reactions differ.

explanation: