What is the molarity of a 2.0 l sodium hydroxide solution containing 10.0 grams of solute?
a.0.80
b.0.13
c.5.0
d.0.25

Molar mass NaOH ( sodium hydroxide) = 40.0 g/mol

Number of moles:

n = mass / molar mass

n = 10.0 / 40.0

n = 0.25 moles

Volume = 2.0 L

Molarity = number of moles / volume in liters

M  = 0.25 / 2.0

M = 0.125  M

answer D

hope this helps!

D-no effect on the rate