He pka values of a compound with two ionizable groups are pk1 = 4.10 and pk2 between 7 and 10. a biochemist has 10 ml of a 1.0 m solution of this compound at a ph of 8.00. she adds 10.0 ml of 1.00 m hcl, which changes the ph to 3.20. what is pk2?

For the reaction of weak acid:

The Henderson-hasselbalch equation is:

The concentration ratio at is:

Substituting the values:

Now, for calculating the pk_2 value:

Thus, .

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

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