Methanol enters a distillation column at 43 c. the column does not have a reboiler and uses open steam for heating. the column is at 101.3 kpa. the steam is pure water and is a saturated vapor. the distillate product is 99 mol% methanol and is a saturated liquid. the bottoms is 2.0 mol% methanol and, since it leaves an equilibrium stage,

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%