Chemistry, 12.07.2019 22:00, ayoismeisjjjjuan
What is the h oh ph and poh of a 0.005m solution of calcium hydroxide?
Answers: 1
![[OH^{-}]= 0.01M or 1.0\times 10^{-2}M](/tpl/images/0082/4318/bc443.png)
![[H^{+}]= 1.0\times 10^{-12}M](/tpl/images/0082/4318/aee4e.png)
) is a strong base that dissociates completely.
![[OH^{-}] = 0.005\times 2](/tpl/images/0082/4318/84dc9.png)
= 0.01M or 
![[H^{+}] = \frac{Kw}{[OH^{-}]}](/tpl/images/0082/4318/e9535.png)
![[H^{+}] = \frac{(1\times 10^{-14})}{[OH^{-}]}](/tpl/images/0082/4318/3f081.png)
![[H^{+}] = \frac{(1\times 10^{-14})}{[0.01]}](/tpl/images/0082/4318/e74d5.png)
![[H^{+}] = 1.0\times 10^{-12}M](/tpl/images/0082/4318/a5f50.png)
![pH = -log[H^{+}]](/tpl/images/0082/4318/8d3ec.png)
![pH = -log[1.0\times 10^{-12}]](/tpl/images/0082/4318/9b8a0.png)
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