If 18.5 grams of cucl2 react with 22.8 grams of nano3, what mass of nacl can be formed? cucl2 + nano3 → cu(no3)2 + nacl

- 15.7 grams of NaCl can be formed.

Solution:- The balanced equation is:

From this balanced equation, there is 1:2 mol ratio between and .

Let's calculate the grams of NaCl for the given grams of both the reactants using stoichiometry and see which one gives least amount of it. The least amount of NaCl formed would be the answer to our problem.

The calculations are as follows:

= 16.1 g NaCl

= 15.7 g NaCl

From above calculations, sodium nitrate is limiting as it gives least amount of NaCl.

So, 15.7 grams of NaCl can be formed from given grams of the reactants.

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the scientist could experiment with moth repellent or oter ways to keep the moths away, but that would not answer his original question.