Let us assume that fe(oh)2(s) is completely insoluble, which signifies that the precipitation reaction with naoh(aq) (presented in the transition) would go to completion. fe2+(aq)+2naoh(aq) → fe(oh)2(s)+2na+(aq) if you had a 0.500 l solution containing 0.0230 m of fe2+(aq), and you wished to add enough 1.29 m naoh(aq) to precipitate all of the metal, what is the minimum amount of the naoh(aq) solution you would need to add? assume that the naoh(aq) solution is the only source of oh−(aq) for the precipitation.
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Let us assume that fe(oh)2(s) is completely insoluble, which signifies that the precipitation reacti...
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