How much heat is required to raise the temperature of 100 grams of water from, 25c to 82 c?

- 23.8 kJ of heat is required to raise the temperature of water.

Solution:- We have been given with grams of water, it's initial and final temperature and asked to calculate the heat required to raise it's temperature. Here, lower degree C water is changing into higher degree C water. So, the formula used to calculate the heat is:

Where, q is the heat energy, m is mass, c is specific heat of water and delta T is change in temperature.

m = 100 grams

= 82 - 25 = 57 degree C

q=?

Let's plug in the values in the formula and do the calculations:

q = 23848.8 J or 23.8 kJ

So, 23.8 kJ of heat is required to raise the temperature of 100 g of water from 25 to 82 degree C.

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explanation:

wisjndnfnnjjdjdjxn

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole