- (a) 2X mol, (b) 3X mol, (c) 12X mol, (d) 342.15X g and (e) 96X g
Solution:- (a) The dissociation equation for the given compound is written as:
From this equation, there is 1:2 ratio between the aluminium sulfate and aluminum ion. So, the number of moles of Al ion in the X moles of the compound would be:
= 2X moles of Al ion
So, there would be 2X moles of Al ions in the X moles of the compound.
(b) From the equation, there is 1:3 mol ratio between aluminum sulfate and sulfate ion. So, the number of moles of sulfate ion in the X moles of the compound would be:
=
So, there would be 3X moles of the sulfate ion in X moles of the compound.
(c) There are 12 moles of O atom in 1 mol of the compound. So, moles of O atom in X moles of compound would be:
= 12X moles of O atom
So, there would be 12X moles of O atom in X moles of the compound.
(d) Molar mass of aluminum sulfate is 342.15 gram per mol. It means the mass of 1 mol of the compound is 342.15 g. So, the mass of X moles of the compound would be:
= 342.15X g of
So, there are 342.15X g of aluminium sulfate in X moles of it.
(e) From part c, there are 12X moles of O in X moles of the compound and the atomic mass of O is 8. So, the grams of O would be:
= 96X g of O
So, the mass of O in the X moles of the compound would be 96X g.