What5 mass of water at 100c can be vaporized by the addition of 45 kcal of heat?

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83.3 g of water can be vaporized by the addition of 45 kcal of heat at 100° C

Explanation: -

Heat of vaporization = 540 Cal / g.

Heat supplied = Q = 45 Kcal = 45 x 1000 Cal

Mass of water= Heat supplied / Heat of vaporization

= 45 x 1000 Cal / (540 Cal /g)

= 83.3 g

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !