36 g of water vapor takes up how many liters at room temperature and pressure of 293k and 100 k pa

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48.72 L

Explanation:-

We need to use the relation PV = nRT

We are given Pressure P = 100 KPa.

We are given Temperature T = 293 K

We know Universal Gas constant R = 8.314 L KPa K-1 mol-1

Mass of water = 36 gram

Chemical formula of water = H2O

Molecular weight of water = 1 x 2 + 16 x 1 = 18 g / mol

Number of moles of water = 36 gram / (18 g / mol)

= 2 mol

Plugging in the values we get

100 KPa x V = 2 mol x 8.314 L KPa K-1 mol-1 x 293 K

V = (2 mol x 8.314 L KPa K-1 mol-1 x 293 K) / (100 KPa)

= 48.72 L

i believe the answer is a.