The resulting atomic number of an element that emits 1 alpha particle, 1 positron, and 3 beta particles is

-

Thus the resulting atomic number of an element that emits 1 alpha particle, 1 positron, and 3 beta particles is the same as original.

Explanation: -

Let the mass number be A and the atomic number be Z.

When an alpha particle is emitted, the mass number decreases by 4 and the atomic number decreases by 2.

Thus after alpha particle the new mass number = A - 4

Thus after alpha particle the new atomic number = Z - 2

When a positron is emitted, the atomic number only decreases by 1.

Thus after positron emission the new mass number = A - 4

Thus after positron emission the new atomic number = Z - 2 - 1

= Z - 3

When a beta particle is emitted, the atomic number increases by 1.

For 3 beta particles, the atomic number will increase by 3.

Thus after beta particle emission the new mass number = A - 4

Thus after beta particle emission the new atomic number = Z - 3+3

= Z

Thus the resulting atomic number of an element that emits 1 alpha particle, 1 positron, and 3 beta particles is the same as original.

i believe it is 40–40–20%

explanation:

the answer is c i believe