"acid is responsible for the odor in rancid butter. a solution of 0.25 m butyric acid has a ph of 2.71. what is the ka for"

Dissociation of butyric acid can be represented as:

HC₄H₇O₄> H⁺ + C₄H₇O₄⁻

So its dissociation constant can be calculated as:

Ka={[H⁺][C₄H₇O₄⁻ ]}/[HC₄H₇O₄]

As pH = -log[H⁺]

2.71 = -log[H⁺]

[H⁺]= 0.0019

[H⁺]=[C₄H₇O₄⁻ ]=0.0019

As [HC₄H₇O₄]= 0.25M

So Ka={[H⁺][C₄H₇O₄⁻ ]}/[HC₄H₇O₄]

=(0.0019×0.0019)/0.25

=0.000014

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.