Agummie bear was tested through a flame-calorimeter test. the bear had a mass of 1.850 grams and the temperature of 100.0 milliliters of water increased by 15.0 degrees celsius. how many calories were in the gummie bear? show all of your calculations.

- 1500 calories

Solution:- mass of bear = 1.850 g

volume of water = 100.0 mL

Density of water is 1.00 g/moL. So, mass of water would be 100.0 g.

delta T for water = 15.0 degree C

specific heat capacity for water is 1 cal/(g* degree C)

q = m x c x delta T

where, q is the heat energy, m is mass, c is specific heat capacity and delta T is change in temperature.

for water, q = 100.0 x 1 x 15.0

q = 1500 calorie

heat gained by water = heat lost by bear

So, the 1.850 g bear has 1500 cal or 1.50 Cal.

(Where, 1 Cal = 1000 cal)

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.