If 5.88 grams of zn react with 5.03 grams of s8 to produce 7.25 grams of zns, what are the theoretical yield and percent yield of this reaction? be sure to show the work that you did to solve this problem. unbalanced equation: zn + s8 yields zns

Note that there are 3 significant figures stated in the question. Therefore, the answers provided will be kept to 3 significant figures.

Balance the equation first:

One mole of Zinc reacts with one mole of octasulfur to create a mole of zinc sulfide. There is one part zinc and 8 parts of sulfur, and it results in 8 parts of zinc sulfide, so you will need to create eight parts of zinc. The following chemical equation is balanced:

5.88 grams of zinc react with 5.03 grams of octasulfur to produce 7.25 grams of zinc sulfide. To find the theoretical yield of the reaction, convert the grams into moles by dividing the grams present by the molar mass and moles in the equation:

There are 0.0889 moles of zinc in this equation, and it will react with 0.0112 moles of octasulfur.

There are 0.0196 moles of octasulfur in this equation.

There is an excess of octasulfur, as you need more moles of octasulfur than moles of zinc to complete the equation. Therefore, you will use moles of zinc to find the theoretical yield:

The theoretical yield is 8.76 grams of zinc sulfide.

To find the percent yield, divide the result from the question by the theoretical yield:

Multiply this decimal by 100 for the percentage:

The percent yield is 82.8%.

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.