Solve this stoichiometry problem solve the following problem showing all of your work and including all units. you can solve the problem in several steps or as a tandem conversion problem. how many grams of br2 are needed to completely convert 15.0 g al to albr3 ? al (s) + br2 (l) --> albr3 (hint: the equation is not balanced)

Answer : The balanced equation is;

2Al + 3 ----> 2Al.

So now, to calculate how many grams of will be needed to completely convert 15 g of Al,

In the reaction 2 moles of Al and 3 moles of will be needed to produce 2 moles of Al.

So, (15.0 g Al) X (1 mole Al / 26.98 g Al) X (3 moles / 2 moles Al) X (159.81 g / 1 mole )

= 133 g

Hence, 133g of will be needed to completely convert 15 g of Al into Al.

6.4 cm (max) - 25 cm (min)